'''

A0 = dict(zip(('a', 'b', 'c', 'd', 'e'), (1, 2, 3, 4, 5)))
A1 = range(10)
A2 = [i for i in A1 if i in A0]
A3 = [A0[s] for s in A0]
A4 = [i for i in A1 if i in A3]
A5 = {i:i*i for i in A1}
A6 = [[i, i*i] for i in A1]

'''

'''

A0 = {'a': 1, 'b': 2, 'c': 3, 'd': 4, 'e': 5}
(字典键值对由zip函数生成)

A1 = range(0, 10)
(Python 3 中range返回迭代器，非列表)

A2 = []
(A0 的键为字符，A1 的元素为整数，无交集)

A3 = [1, 2, 3, 4, 5]
(遍历 A0 的键，提取对应值)

A4 = [1, 2, 3, 4, 5]
(A1 中存在于 A3 的元素)

A5 = {0: 0, 1: 1, 2: 4, 3: 9, 4: 16, 5: 25, 6: 36, 7: 49, 8: 64, 9: 81}
(平方映射字典)

A6 = [[0, 0], [1, 1], [2, 4], [3, 9], [4, 16], [5, 25], [6, 36], [7, 49], [8, 64], [9, 81]]
(嵌套列表，每个元素为[i, i*i])

'''